A1.5 g iron nail is heated to 95.0 °c and placed into a beaker of water. calculate the heat gained by the water if the final equilibrium temperature is 57.8 ° c. the specific heat capacity of iron = 0.449 j/ g ° c, and the specific heat capacity of water = 4.18 j/ g ° c

Heat gained by water= 25.1 J

Explanation:

As per the law of conservation of energy

Heat gained by water= Heat lost by the nail

Heat lost by nail= Q= m c ΔT

m= mass of nail= 1.5 g

c= specific heat capacity of nail=0.449 j/ g °C

ΔT= change in temperature=57.8-95= -37.2° C

Q=1.5 (0.449)(-37.2)

Q=-25.1 J

This is negative because the heat is lost by the nail. Same amount of heat is gained by the water.

so heat gained by water=25.1 J

seeing the graph would