An organ pipe open at both ends has a radius of 4.0 cm and a length of 6.0 m. what is the frequency (in hz) of the third harmonic? (assume the velocity of sound is 344 m/s.)

When air is blown into the open pipe,

L =

where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation

⇒λ=

Note here that n=1 is for fundamental, n=2 is first harmonic and so on..

⇒ third harmonic will be n=4

Given L=6m, n=4, solving for λ we get:

λ= =3m

Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:

c=f.λ Or f=

⇒f=

≈115 Hz

it breaks and dirupture other materials and other sencews from the bottom

report!

explanation:

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