Aspeedboat travels from the dock to the first buoy, a distance of 20 meters, in 18 seconds. it began the trip at a speed of 0 m/s. by the time it reached the buoy, it was going 10 m/s. what was the average velocity of the boat? -3.33 m/s2 -1.11 m/s +1.11 m/s +3.33 m/s

Explanation:

The average speed is define as the total distance traveled divided by the total time spends, from the problem we know that the total distance is 20 meters, and the total time is 18 seconds, we just have to find the quotient between and them:

Therefore the average velocity is +1.11 m/s.

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

distance = 150m

displ = root (50 ^2 + 100^2)

root(2500+10000)

root 125000