Asled weighing 1.0 n is held in place on a frictionless 20.0° slope by a rope attached to a stake at the top. the rope is parallel to the slope. what is the normal force of the slope acting on the sled?

for the above situation we will draw a force diagram first

As per the force diagram we can see that normal force due to the inclined wedge is counter balanced by component of the weight.

So by the force diagram we can write

N =

here mg = 1 N

N = 1* cos20

N = 0.94 N

i'm on my way to history not a mistory.