Aforce on a particle depends on position such that f(x) = (3.00 n/m2)x 2 + (3.50 n/m)x for a particle constrained to move along the x-axis. what work is done by this force on a particle that moves from x = 0.00 m to x = 2.00 m?

Work done, W = 15 joules

Explanation:

It is given that,

The force acting on a particle depends on position such that,

Let W is the work done by this force on a particle that moves from x = 0.00 m to x = 2.00 m. The expression for work done is given by :

W = 15 Joules

So, the work done by this force on a particle is 15 joules. Hence, this is the required solution.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

i believe the answer is a hope it and is correct