Acar is moving 5.82 m/s when it accelerates at 2.35m/s^2 for 3.25s. how far does it travel?

Distance, s = 31.32 meters

Explanation:

It is given that,

Initial velocity of the car, u = 5.82 m/s

Acceleration of the car,

Time taken, t = 3.25 s

We need to find the distance travelled by the car. Let s denotes the distance covered by the car. It can be calculated using the second equation of motion as :

s = 31.32 meters

So, the distance travelled by the car is 31.32 meters. Hence, this is the required solution.

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be