Infants and children require daily allowance of 8.00 * 10^-6 mole of copper per kiogram of body weight. Calculate for a 10kg infant, the mass of copper required per day. Please show working out thanks.

0.00508368 grams

Explanation:

From the question we are told that the daily allowance for infants and children is  8.00 × 10⁻⁶ mole of copper per kiogram of body weight.

Since this value is given in moles, we have to convert it to mass

Molar mass of a compound = mass in grams / no of moles of the compound.

So, Molar mass of copper = 63.546

No of moles of copper per kg = 8.00 × 10⁻⁶ mole

63.546 = mass/ 8.00 × 10⁻⁶ mole

Cross multiply

Mass of copper per kg body weight = 8.00 × 10⁻⁶ × 63.546

= 0.000508368 grams

Hence, the daily allowance of copper required for infants or children per kg of weight = 0.000508368 grams.

For a 10 kg infant this is calculated as:

If 1 kg per weight of an Infant = 0.000508368grams

10 kg =

We cross multiply

10 kg × 0.000508368 grams

= 0.00508368 grams.

Therefore, the mass of copper required per day for a 10 kg child is 0.00508368 grams

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