Acampground owner plans to enclose a rectangular field adjacent to a river. the owner wants the field to contain 180,000 square meters. no fencing is required along the river. what dimensions will use the least amount of fencing?

Calling x and y the two sizes of the rectangular field, the problem consists in finding the minimum values of x and y that give an area of . 
The area is the product between the two sizes:
(1)
While the perimeter is twice the sum of the two sizes:
(2)

From (1) we can write

and we can substitute it into (2):


To find the minimum value of the perimeter, we have to calculate its derivative and put it equal to zero:

The derivative of the perimeter is

If we require p'(x)=0, we find


And the other side is


This means that the dimensions that require the minimum amoutn of fencing are (424.26 m, 424.26 m), so it corresponds to a square field.

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!

$22. if larry's profit were to minimize by one for every hour his store were to be closed, we would subtract 30 by 8.