Adog is attached to a 49 foot rope fastened to the outside corner of a fenced-in garden that measures 42 feet by 51 feet. assuming that the dog cannot enter the garden, compute the exact area that the dog can wander.

5698 sq. cm is the answer.

Step-by-step explanation:

Since dog cannot enter the garden therefore and it can wander as maximum as its rope can move which actually makes a circle. therefore it makes 3rd fourth of circle  with radius 49 cm and then one fourth part  circle with radius 7 cm  with another corner ( From the corner 42 foot away from where the leash begins ,the dog has only 49 - 42 = 7 foot of leash left )

So total area covered by dog = +

                                                 =

                                                  =  

                                                  = 37  (49) (

                                                   = 37x7x22

                                                   =5698  sq cm

c

step-by-step explanation:

at least i think its

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: