Therefore, the volume of one pyramid must equal one-sixth the volume of the cube, or a: 1/6 (b)(b)(2h) or 1/3bh b: 1/6 (b)(b)(6h) or bh c: 1/3 (b)(b)(6h) or 1/3 bh d: 1/3 (b)(b)(2h) or 2/3 bh

A: 1/6 (b)(b)(2h) or 1/3Bh

Step-by-step explanation:

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a

Step-by-step explanation:

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m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°