Mathematics, 21.07.2019 12:00 barry14201
Y= 2f(g(x)) dy/dx = 2f'(g(x)) * g'(x) differentiate again: d^2y/dx^2 = 2f''(g(x)) * g'(x) * g'(x) + 2f'(g(x)) * g''(x) d^2y/dx^2 = 2f''(g(x)) * (g'(x))^2 + 2f'(g(x)) * g''(x) am i correct in saying answer d?
Answers: 1
Mathematics, 21.06.2019 19:10
The triangles in the diagram are congruent. if mzf = 40°, mza = 80°, and mzg = 60°, what is mzb?
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Mathematics, 22.06.2019 00:00
Cody ran nine miles on his first day of training. the next day he ran 1/8 that distance. how far did he run the second day?
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Y= 2f(g(x)) dy/dx = 2f'(g(x)) * g'(x) differentiate again: d^2y/dx^2 = 2f''(g(x)) * g'(x) * g'(x) +...
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