Which set of ordered pairs could be generated by an exponential function? (0, 0), (1, 1), (2, 8), (3, 27) (0, 1), (1, 2), (2, 5), (3, 10) (0, 0), (1, 3), (2, 6), (3, 9) (0, 1), (1, 3), (2, 9), (3, 27)

For this case we must find the set of ordered pairs that form an exponential function.

When observing, the last set of ordered pairs is an exponential function of the form:

For x = 0:

We have the ordered pair:

For x = 1:

We have the ordered pair:

For x = 2:

We have the ordered pair:

For x = 3:

We have the ordered pair:

The set of ordered pairs that form an exponential function is:

a and c

for infinitely many solutions we require both left and right sides to be equal

distribute and simplify

a

14 - 8x = 20 - 8x - 6 = 14 - 8x ← both sides equal so infinite solutions

b

6x - 54 = 6x - 54 + x = 7x - 54 ← not equal

c

4x + 16 = 4x + 10 + 6 = 4x + 16 ← both sides equal so infinite solutions

d

5x - 40 + 10 = 5x + 10

5x - 30 = 5x + 10 ← not equal

none of the above chief keef