The vertex angle of an isosceles triangle is 20° less than the sum of the base angles. which system of equations can be used to find the measure of the vertex and base angles? a) v + 2b = 180; 2b - 20 = v b) v + 2b = 180; 2b + 20 = v c) v - 2b = 180; v + 2b = -20 d) v - 2b = 180; -2b - 20 = v

The answer to the above question can be explained as under -

We know that, the sum of angles of triangle is 180°.

So, vertex angle plus base angles are equal are equal to 180°.

Let the vertex angle be represented by "v" and base angles be represented by "b".

Thus,  v + b + b = 180°

So,  v + 2b = 180°

Next, the question says, the vertex angle is 20° less than the sum of base angles.

Thus, 2b - 20° = v

Thus, we can conclude that the correct option is A) v + 2b = 180°, 2b - 20° = v

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6