Aline has a slope of - 3/5. which ordered pairs could be points on a line that is perpendicular to this line? check all that apply. (–8, 8) and (2, 2) (–5, –1) and (0, 2) (–3, 6) and (6, –9) (–2, 1) and (3, –2) (0, 2) and (5, 5)

(–3, 6) and (6, –9) and  (0, 2) and (5, 5)

Step-by-step explanation:

Given : Slope = .

To find: Which ordered pairs could be points on a line that is perpendicular to this line.

Solution : We have given that  Slope = .

Slope = .

For (–8, 8) and (2, 2)

Slope = .

Slope = .

Slope = .

For (–5, –1) and (0, 2).

Slope = .

Slope = .

For, (–3, 6) and (6, –9)

Slope = .

Slope = .

Slope = .

For (–2, 1) and (3, –2)

Slope = .

Slope  = .

For (0, 2) and (5, 5)

Slope = .

Slope =  .

Therefore,  (–3, 6) and (6, –9) and  (0, 2) and (5, 5)

answer: answer is c!

ok i got to organize the

3/15 and 12/55

3*

aha

3*4 equals 12 but not

a: no

b:

8/24 12/35

no

gautie

it's c

5/18 = 25/90

5*5=25

18*5 = 90

hope that you!

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step-by-step explanation: