What is the height of a triangle that has an area of 60 yd squared and a base with a length of 12 yd

The answer is:  " 10 yd. " . 

The height of the triangle is:  " 10 yd " .

Explanation:

The formula for the area, "A", of a triangle is:

          →   " A = (b * h) / 2  " ; 

in which:  " A = area (in square units;  in this case;  "yd² " ; 
                       
                      = " 60 yd² " {given} ; 

                  "b = base length = 12 yd" {given} ; 

                  "h = [perpendicular] height ; for which we shall solve;


 →  A = (b * h) / 2 ;  

 → Rearrange the equation to isolate "h" on one side of the equation; since we need to solve for "h" (height) ; 

→  Multiply each side of the equation by "2" ; 

→  2 * A = 2 * [ (b * h) / 2 ] ;

to get:

→  2A  = b * h ; 

↔  b * h = 2A ; 

Divide each side of the equation by "b" ; 
          to isolate "h" on one side of the equation; 

→  (b * h) / b  =  2A / b ; 

→  h = 2A / b ; 

Now, plug in our given values for "A" and "b" ;  
    to solve for "h" ; 

→  h = (2* 60 yd²) / (12 yd) ; 

         = (120 yd²) / (12 yd). 

         = 10 yd.

→  h = 10 yd.

The answer is:  " 10 yd. " . 

The height of the triangle is:  " 10 yd " .