A3-lb force acting in the direction of the vector (3,-1) moves an object just over 9 ft from point (0,5) to (6,-2). find the work done to move the object to the nearest foot-pound

The Work done to move the object is  

Step-by-step explanation:

Given;

Force F=3

Vectors of F= (3,-1)

Moves object to a distance=9

Let A and B be the displacements Vectors

A= (0,-5)

B= (6,-2)

To Find:

Work done in foot-pounds

Solution:

Work done

Direction of force vector= (3,-1)  (i, j)  

                                        =3i-j

Unit of force vector

Force vector=(Force/Unit Vector)Direction of  force vectors

                   F=

Direction of motion vector= (B-A)  

                                          = (6,-2)-(0,-5) x i,j)

                                          =(6-0),(-2-5) x (i, j)

                                          =(6,-7) x (i, j)

                                          =6i-7j

Unit of motion vector

Motion Vector= (Distance moved by the object/Unit motion vector) × (Direction of motion vectors)

Workdone

Result:

   Work done to move an object

Step-by-step explanation:

The work done to move the object is:

The angle of the force with respect to change in the position vector is:

The magnitude of the work done is:

there is nothing below so i cannot

step-by-step explanation:

there are 70 more legs than eyes at the dog show (196 – 126 = 70). dogs have two more legs than eyes, and humans have the same number of legs as eyes. thus 70 is twice the number of dogs at the show, so the number of dogs is half of 70, which is 35. to get the number of humans, subtract 35 from 63: 63 – 35 = 28.

step-by-step explanation: