Which is a zero of the quadratic function f(x) = 16x2 + 32x − 9? x = –5.25 x = –2.25 x = –1.25 x = –0.25

Group terms that contain the same variable,

f(x) = (16x² + 32x) − 9 

Factor the leading coefficient of each expression

f(x) =16*(x² + 2x) − 9 

Complete the square. Remember to balance the equation 

f(x) =16*(x² + 2x+1-1) − 9 

f(x) =16*(x² + 2x+1) − 9-16 

Rewrite as perfect squares

f(x) =16*(x+1)² − 25

 to find the zero of the quadratic function equate the equation to zero

16*(x+1)² − 25=0> 16*(x+1)² = 25> (+/-)4*(x+1)=5

(+)4x+4=5> 4x=1> x=1/4> x=0.25

(-)[4x+4]=5> -4x-4=5> -4x=9> x=-9/4-2.25

the zero of the quadratic function are

x=1.25

x=-2.25

the answer is

x=-2.25

the answe is x = –2.25

Step-by-step explanation:

okay wait before i answer, is this for your points on a graph?

the correct answer is 5 6 and 7