Triangle abc has vertices a(–2, –3), b(–5, –3), and c(–4, –2). the triangle is rotated 90° counterclockwise around the origin. what is the correct set of image points for triangle a’b’c’? a’(3, 2), b’(3, 5), c’(2, 4) →→a’(3, –2), b’(3, –5), c’(2, –4)←← a’(–3, –2), b’(–3, –5), c’(–2, –4) a’(–3, 2), b’(–3, 5), c’(–2, 4) answer is b : )

The answer is the option B: A'(3, -2), B'(3, -5), C'(2, -4).

The explanation is shown below:

1. You must apply  the following rule of rotation when the figure is rotated 90° counterclockwise around the origin:

→

2. Then, as you can see, you must switch and and multiply by -1.

3. Keeping this on mind, you have that the vertices of the triangle A'B'C' are the following:

A(-2,-3)→A'(3,-2)

B(-5,-3)→B'(3,-5)

C(-4,-2)→C(2,-4)

4. Therefore, you can conclude that the answer is the option B.

x = 12

y = 1

for the points!

answer:   2 multiplied by x =24

step-by-step explanation: