Alex and jim have equal amounts of money. each day, alex spends $5 and jim spends $3. when alex has $8 left, jim has 4 times as much money left as alex. how much money does each boy have at first?

I don't think they would have equal amounts at first since the numbers are different. This is what I did to find out how much $ each had at the first place: 

Alex spend $5 a day x 7(days of the week)= $35 + $8 = $43 ( total $ Alex had at the beginning).

Jim spend $3 x 7 = $21 Since Jim left 4 times more than Alex which is $8 you multiply $8 x 4= $32+ $21= $53. That's what Jim had at first.

I hope I helped :)

choice b is correct

step-by-step explanation:

we have been given the following system of linear inequalities;

we are required to graphically determine the solution to these system of inequalities. using a graphing tool, the solution is as shown in the attachment below;