You compared the two functions below. f(x) = 1.2t      g(x) = 1.2t-5 what did subtracting 5 in the exponent do to the function? check all that apply. a. it shifts the graph of f left 5 units. b. it shifts the graph of f right 5 units. c. it multiplies all the y-values by 5. d. it divides all the y-values by 5. e. it multiplies all the y-values by 1.25. f. it divides all the y-values by 1.25.

B. It shifts the graph of f right 5 units.

F. It divides all the y-values by 1.25.

Step-by-step explanation:

Let me revise your two functions:

f(x) =

g(x) =

So g(x) is the transformed function of f(x), as we know that

In this situation, we subtract 5 from it, so the graph of f right 5 units.

However, it also affect to the value of y, I will rewrite g(x)

g(x) = = * = f(x)

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6