Mathematics, 22.07.2019 15:30 shira35
Find the vertex, focus, directrix, and focal width of the parabola. x = 10y2 vertex: (0, 0); focus: one divided by forty comma zero; directrix: x = negative one divided by forty; focal width: 0.1 vertex: (0, 0); focus: one divided by ten comma zero; directrix: x = negative one divided by ten; focal width: 0.1 vertex: (0, 0); focus: one divided by forty comma zero; directrix: x = one divided by forty; focal width: 40 vertex: (0, 0); focus: zero comma one divided by forty; directrix: y = negative one divided by forty; focal width: 40
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9.4.34 question to estimate the height of a stone figure, an observer holds a small square up to her eyes and walks backward from the figure. she stops when the bottom of the figure aligns with the bottom edge of the square, and when the top of the figure aligns with the top edge of the square. her eye level is 1.811.81 m from the ground. she is 3.703.70 m from the figure. what is the height of the figure to the nearest hundredth of a meter?
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Mathematics, 21.06.2019 22:40
Alina fully simplifies this polynomial and then writes it in standard form. xy2 β 2x2y + 3y3 β 6x2y + 4xy2 if alina wrote the last term as 3y3, which must be the first term of her polynomial in standard form? xy2 5xy2 β8x2y β2x2y
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Find the vertex, focus, directrix, and focal width of the parabola. x = 10y2 vertex: (0, 0); focu...
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