(z-2) (z+6) multiplying polynomials

z2-z-6=0

Two solutions were found :

z = 3
z = -2
Reformatting the input :

Changes made to your input should not affect the solution:

(1): "z2" was replaced by "z^2".

Step by step solution :

Step 1 :

Trying to factor by splitting the middle term

1.1 Factoring z2-z-6

The first term is, z2 its coefficient is 1 .
The middle term is, -z its coefficient is -1 .
The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 .

-6 + 1 = -5
-3 + 2 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2
z2 - 3z + 2z - 6

Step-4 : Add up the first 2 terms, pulling out like factors :
z • (z-3)
Add up the last 2 terms, pulling out common factors :
2 • (z-3)
Step-5 : Add up the four terms of step 4 :
(z+2) • (z-3)
Which is the desired factorization

Equation at the end of step 1 :

(z + 2) • (z - 3) = 0
Step 2 :

Theory - Roots of a product :

2.1 A product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately

In other words, we are going to solve as many equations as there are terms in the product

Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation :

2.2 Solve : z+2 = 0

Subtract 2 from both sides of the equation :
z = -2

Solving a Single Variable Equation :

2.3 Solve : z-3 = 0

Add 3 to both sides of the equation :
z = 3

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )

Ithink it's the first one ( let me know if it right)