If triangle cde is dilated by a scale factor of 1/5 with a center of dilation at vertex e, what is the area of triangle c'd'e'? a) 2 units2 b) 4 units2 c) 8 units2 d) 16 units2

B) 4 units2

Step-by-step explanation:

The resultant triangle frmo the dilatation would have 1/5 of the size on each size, in the original triangle the base is 10 units and the height is 20 units, so 1/5 of 10 would be 2, and 1/5 of 20 would be 4, the resultant triangle from the dilatation at 1/5 would have an area of 4 squared units.

The area of the triangle is calculated with the next formula:

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~