Aset of data has a mean of 56.1. the data follows a normal distribution curve and has a standard deviation of 8.2. find the probability that a randomly selected value is greater than 67.5 a. 0.0823 b. 1.39 c. 0.9177 d. –1.08

A.  0.0823

Step-by-step explanation:

Given : Mean =56.1

Standard deviation =8.2

P(x>67.5) will be found as follows:

The z-score is given by:

Substitute the values of means ans standard deviation in it, we get

As

P(z<1.39)=0.9177

thus:

P(X>67.5)=1-P(z<1.39)

⇒P(X>67.5)=1-0.9177

∴P(X>67.5)=0.0823

450

step-by-step explanation:

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