The equation for a circle with center (h, k) is (x - h)2 + (y - k)2 = r2. if a circle is modeled by the equation x2 + (y + 6)2 = 100, what is the center of the circle? a)(0, 6)b)(6, 0)c)(0, −6)d)(−6, 0)

We know that 
the equation of a circle in standard form is 
(x-h)²+(y-k)²=r²
where (h,k) is the center
and r is the radius

so
x² + (y + 6)² = 100> x² + (y + 6)² = 10²

the center is (0,-6) and the radius is 10 units

the answer is the option
C)(0, −6)

Don’t worry about it

Iwould like to think so. what’s the question you need with?