Mathematics, 23.07.2019 00:30 najashohatee1234
Stephen evaluated (6.34 x 10^-7)(4.5 x 10^3). his work is shown below. which statements describe his errors? check all that apply. (6.34 x 10^-7)(4.5 x 10^3) (6.34 x 4.5)(10^-7 x 10^3) 28.53 x 10^-4 -28.53 x 10^4 -2.853 x 10^3 a. he changed the sign of the coefficient. a negative exponent does not affect the sign of a coefficient in scientific notation. the sign of the exponent determines the direction the decimal is moved in. b. he rewrote -28.53 x 10^4 incorrectly; 28.53 x 10^4 = 2.853 x 10^5. the exponent is increased to account for the extra place the decimal is moved. c. he did not correctly evaluate the exponent. it should be evaluated as (10^-7 x 10^3) = 10^3 since exponents are evaluated using the same operation as the coefficients. d. he got the wrong value for the coefficients; 28.53 x 10^-4 is not possible. the coefficients in scientific notation are always greater than 1, but less than 10. f. he multiplied the coefficients; he should have added 6.34 and 4.5. the product of powers rule states that coefficients are added. keep in mind that there is multiple answers.
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Mathematics, 21.06.2019 14:30
Isee the amount was $90.00 then reduced to $75.00 , what is the percent ?
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Mathematics, 22.06.2019 01:10
Farmers know that driving heavy equipment on wet soil compresses the soil and injures future crops. here are data on the "penetrability" of the same type of soil at two levels of compression. penetrability is a measure of how much resistance plant roots will meet when they try to grow through the soil. compressed soil 2.85 2.66 3 2.82 2.76 2.81 2.78 3.08 2.94 2.86 3.08 2.82 2.78 2.98 3.00 2.78 2.96 2.90 3.18 3.16 intermediate soil 3.17 3.37 3.1 3.40 3.38 3.14 3.18 3.26 2.96 3.02 3.54 3.36 3.18 3.12 3.86 2.92 3.46 3.44 3.62 4.26 use the data, omitting the high outlier, to give a 95% confidence interval for the decrease in penetrability of compressed soil relative to intermediate soil. compute degrees of freedom using the conservative method. interval: to
Answers: 1
Stephen evaluated (6.34 x 10^-7)(4.5 x 10^3). his work is shown below. which statements describe his...
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