Find the value of z. a. 3 b. 6\sqrt{2} c. 2 d. 2\sqrt{2}

So you would first find the length of y.

To do that, use the Pythagorean's Theorem:

a²+b²=c²

in this case, c = 3, and b = 1.

a² + 1² = 3²
a² + 1 = 9
a² = 8
a = √8

Now to find z, use the Pythagorean's Theorem again:

a² + b² = c²

where √8 = a and 8 = b, and z = c.

√8² + 8² = z²
8 + 64 = z²
72 = z²
z = √72

To simplify this, take out the largest perfect square, or 36:

z = √36√2
z = 6√2

So your answer would be B.

Ab=dc ac=de ad=bce i hope this !