Suppose that circles r and s have a central angle measuring 80°. additionally, the measure of the sector for circle r is 32 9 π m2 and for circle s is 18π m2. if the radius of circle r is 4 m, what is the radius of circle s?

alternative method

Let 

rA> radius of the circle R

rB> radius of the circle S

SA> the area of the sector for circle R

SB> the area of the sector for circle S

we have that

rA=4 m

rB=?

SA=32π/9 m²

SB=18π m²

we know that

if Both circle A and circle B have a central angle , the square of the ratio of the radius of circle A to the radius of circle B is equals to the ratio of the area of the sector for circle A to the area of the sector for circle B

 (rA/rB) ^2=SA/SB> rB²=(SB/SA)*rA²> rB²=(18π/32π/9)*4²> rB²=162/2

ok

step-by-step explanation:

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.