What is the axis of symmetry for f(x) = 2x2 − 8x + 8?

F(x)=2x^2-8x+8
This is a quadratic equation, and its graph is a vertical parabola
f(x)=ax^2+bx+c
a=2>0 (positive), then the parabola opens upward
b=-8
c=8

The Vertex is the minimum point of the parabola: V=(h,k)
The abscissa of the Vertex is:
h=-b/(2a)=-(-8)/[2(2)]=8/4→h=2

The axis of symmetry is the vertical line:
x=h→x=2

The axis of symmetry for f(x) = 2x^2 − 8x + 8 is x=2

Then why is the question on here if you know the answer

Where the white dots are is where your points should be plotted.a translation is simply just moving something from one place to another. in this case, you would move each plot point of the original shape 2 units up, and 5 units to the left.