Arocket was launched into the air from a platform above the ground. the height, in feet, of the rocket above the ground t seconds after being thrown can be determined by the expression -16t squared + 64t + 80. what does the 80 in the expression represent?

For this case we have the following expression:
 h (t) = -16t ^ 2 + 64t + 80
 For t = 0 we have:
 h (0) = -16 (0) ^ 2 + 64 (0) + 80
 h (0) = -0 + 0 + 80
 h (0) = 80 feet
 Therefore the number 80 represents the initial height of the rocket
 
 the 80 in the expression represented:
 the initial height of the rocket