Abox contains red apples and green apples .if an apple is picked at random from the box the probability of picking a red apple is 3/8 .which of these best describes the likelihood of picking a green apple?

Question says that there are red apples and green apples in the box.

And the probability of picking a red apple is 3/8

Now as there are only two types of apples

So probability of picking a green apple = 1 - 3/8 = 5/8

Now as we can clearly see that the probability of picking a green apple is more than the probability of picking a red apple.

Hence likelihood of picking a green apple is more LIKELY , then red apple.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)