An airplane is flying from new york city to los angeles. the distance it travels in miles, d, is related to the time in seconds, t, by the equation d = 0.15t. how far would an airplane travel in 30 seconds to new york to los angeles?

4.5 miles.

Step-by-step explanation:

Given : An airplane is flying from New York City to Los Angeles.

The distance it travels in miles, d, is related to the time in seconds, t, by the equation .                                    (1)

To find : The distance traveled by airplane travel in 30 seconds to New York to Los Angeles.

We substitute the value of t= 30 in equation (1) , we get

i.e. the distance traveled by airplane travel in 30 seconds to New York to Los Angeles = 4.5 miles.

Hence, the correct answer is 4.5 miles.

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

i would say b) is your answer

sorry if im wrong

step-by-step explanation: