Need asap a: 10x − 4y = 20 b: 8x + 6y = 14 solve this system of equations using addition. show all of your work. also list the property that you use in each step

X = 44/23 and y= -5/23.

We want the coefficient of one of the variables to be the same in both equations; we can multiply the top equation by 3 and the bottom equation by 2 to make the coefficients of y equal:
3(10x-4y=20) → 30x-12y=60
2(8x+6y=14) →  16x+12y=28

This is possible due to the multiplication property of equality.

Now that the coefficients of y are the same, we can add the equations together (using the addition property of equality):
30x+16x = 60+28 
46x = 88 (addition of like terms)

Divide both sides by 46:
46x/46 = 88/46 (division property of equality)
x = 88/46 = 44/23

Now we substitute x into the first equation:
10(44/23) - 4y = 20
440/23 - 4y = 20

It will be easier to solve this if we have a common denominator; 20 wholes = (20*23)/23 = 460/23;

440/23 - 4y = 460/23

Subtract 440/23 from both sides (subtraction property of equality):
440/23 - 4y - 440/23 = 460/23 - 440/23
-4y = 20/23

Divide both sides by -4 (division property of equality):
-4y/-4 = 20/23 ÷ -4/1
y = 20/23 × -1/4 = -20/92 = -5/23

If jon had $4.00 then takes away $2.25, then he should have $1.75 left. $4.00 - $2.25 = $1.75 hope this ; )