Which direction does the graph of the equation shown below open? y^2-4x+4y-4=0 a. left b. up c. down d. right

We have that
Y²-4x+4y-4=0
you can rewrite the equation as 
4x=y²+4y-4
x=(y²/4)+y-1
x=0.25*(y²+4y)-1
x=0.25*(y²+4y+4-4)-1
x=0.25*(y²+4y+4)-5
x=0.25*(y+2)²-5

the equation of the parabola is of the form
x=a(y-k)²+h
is a horizontal parabola
where
(h,k)-----> is the vertex-----> (-5,-2)
a=0.25
a> 0--------> open to the right

the answer is
the option D. Right

see the attached figure

We need the pictures of the graphs

I’m going to infer you said parallel.solve for yy= -1/2x+7/4lines that are parallel have the same slope, different y intercept.so we know m is -1/2then from there solve for y intercept.