Events a, b, and c in a sample space have p(a)=0.2, p(b)=0.4, and p(c)=0.1. find p(a ∪ b ∪ c. if a and b are mutually exclusive, a and c are independent, and b and c are independent.

If and are mutually independent, then and .

If and are independent, then . Ditto for and .

The inclusion/exclusion principle says that



Since and are mutually exclusive, their intersection is the empty set. It then follows that also is the empty set, so the last probability is also 0.

Plug in what we know:

The answer is 270 cars.you can do this by making a proportional relationship. for instance, 200 is the whole we are using, so on a “number line” 200 would be over 100%. now, since he sells 35% more, add 35% to 100% to get 135% on the other side of the “number line” on the bottom half, leaving the top half empty.cross multiply 200 by 135 then divide by 100 to get your answer. i hope this , if it did, , if you don’t mind, giving me brainiest! 200/100% } 200 • 135 /100 ? /135%