Alinear function has an x-intercept of 12 and a slope of 3/8. how does this function compare to the linear function that is represented by the table? x= -2/3, -1/6, 1/3, 5/8. y=-3/4, -9/16, -3/8, -3/16. it has the same slope and the same y-intercept. it has the same slope and a different y-intercept. it has the same y-intercept and a different slope. it has a different slope and a different y-intercept.

We rewrite the statement correctly:
 "A linear function has an y-intercept of 12 and a slope of 3/8"
 Therefore, the linear function is:
 y = (3/8) x + 12
 We look for the linear function of the table:
 y-yo = m (x-xo)
 Where,
 m = (y2-y1) / (x2-x1)
 m = ((- 3/8) - (- 3/4)) / ((1/3) - (- 2/3))
 m = ((- 3/8) - (- 6/8)) / (3/3)
 m = ((- 3 + 6) / 8) / (1)
 m = 3/8
 (xo, yo) = (- 2/3, -3/4)
 Substituting:
 y + 3/4 = (3/8) (x + 2/3)
 y = (3/8) x + 2/8 - 3/4
 y = (3/8) x + 1/4 - 3/4
 y = (3/8) x + -2/4
 y = (3/8) x + -1/2
 The lines are:
 y = (3/8) x + 12
 y = (3/8) x + -1/2
 
 It has the same slope and a different y-intercept

hope it is correct if not i'm srry i tried to