Wednesday, a local deli offered a lunch special consisting of a ham or roast beef sandwich with or without american cheese on toast, a roll, or a bagel. thursday, the owner of the deli decided to offer customers the same options of meat and bread but let customers choose to have their sandwiches with or without either american or swiss cheese. - how many more one meat, one cheese, one bread sandwich combinations are offered thursday than wednesday? a: 1 b: 6 c: 12 d: 18

The answer is B, or 6

To solve this problem, you just have to solve for probability by multiplying the values.

For Wednesday, you have 2 meats, 1 cheese, and 3 breads. So the amount of options on Wednesday is 2 • 1 • 3 = 6

For Thursday, you have 2 meats, 3 breads, and 2 cheeses. This means that you have 2 • 3 • 2 = 12 options on Thursday to have a sandwich with one meat, one bread, and one cheese.

So now, you know the options and can find the difference. 12 – 6 = 6, so the answer is B, or 6 more options