Y=2x^2+16x+31 graph from standard form

Standard form: y = ax² + bx + c

vertex ( -b/2a , y)

this equation;
a = 2
b = 16
c = 31

so the x-coordinate of the vertex is ...
= -16/2(2)
= -16/4
= -4

Use the x-coordiante to find the vertex y-ccordinate

y = 2(-4)² + 16(-4) + 31
y = 32 - 64 + 31
y = -1

Vertex is (-4, -1)

do  a rough sketch of the graph using the location of the vertex. "a" is positive so the parabola is right-side up.

Type the equation into https://www.desmos.com/calculator
if you have trouble still

Standard form: y = ax² + bx + c

vertex ( -b/2a , y)

this equation;
a = 2
b = 16
c = 31

so the x-coordinate of the vertex is ...
= -16/2(2)
= -16/4
= -4

Use the x-coordiante to find the vertex y-ccordinate

y = 2(-4)² + 16(-4) + 31
y = 32 - 64 + 31
y = -1

Vertex is (-4, -1)

do  a rough sketch of the graph using the location of the vertex. "a" is positive so the parabola is right-side up.

Type the equation into https://www.desmos.com/calculator
if you have trouble still

A: 0.26 would be the answer

No i refuse to tell you the answer but the estimate is 10