Use graphs and tables to find the limit and identify any vertical asymptotes of the function. limit of 1 divided by the quantity x minus 1 squared as x approaches 1.

vertical asymptote at x=1

Step-by-step explanation:

First we find out limit approaches from right

BEcause the denominator is a positive quantity because it has square

we find out limit approaches from right

so limit is infinity

To find out vertical asymotote , we take the denomintor and set it =0

(x-1)^2=0

Take square on both sides

(x-1) = 0

add 1 on both sides

x=1

So vertical asymptote at x=1

da freeck kinda math is this just drop out

step-by-step explanation:

any options?

step-by-step explanation: