Find the quotient of quantity of 6 times x to the 3rd power minus 18 times x to the 2nd power minus 12 times x all over negative 6 times x. −x2 − 3x − 2 x2 − 18x − 12 −x2 + 18x − 12 −x2 + 3x + 2

Well that's a handful. Let's try to rewrite this with numbers and signs, and factor out the 6x. With the 6x factored out we can eliminate the 6 from the numerator and denominator.

[tex] \frac{6 x^{3} - 18 x^{2} -12x }{-6} = \frac{6x( x^{2} -3x - 2)}{-6} = -x(x^{2} - 3x - 2)