Helppp the net of a solid figure is shown below: four squares are shown side by side in a row. the second square has a square above it and a square below it. all the squares have side length equal to 3 inches which calculation will give the total surface area of the solid figure? pick from the 4 below 3 × 6 × 6 square inches 6 × 3 × 3 × 3 square inches 3 × 6 × 6 × 6 square inches 6 × 3 × 3 square inches

6 × 3 × 3  square inches

Step-by-step explanation:

The figure contains total six squares of  dimension 3 each.

Total surface area of figure=Area of 6 squares

Area of 1 square= 3 × 3  square inches

Hence, area of 6 squares= 6 × 3 × 3  square inches

Hence, total surface area of figure is:

6 × 3 × 3  square inches

gdp is the best phrase!

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2