Arectangular garden is 5 feet long and 3 feet wide. a second rectangular garden has dimensions that are double the dimensions of the first garden. what is the percent of change in perimeter from the first garden to the second garden?

We know that
the dimensions of the first garden are> 5 ft x 3 ft
perimeter first garden=2*[5+3]> 16 ft

the dimensions of the second garden are---> (5*2) ft x (3*2) ft
10 ft x 6 ft
perimeter second garden=2*[10+6]> 32 ft
so

1f 16 ft (perimeter garden 1)> 100%
then 32 ft (perimeter garden 2)> X%
X=32*100/16X=200%
[the percent of change in perimeter]=   200%-100%> 100%

the answer is
100% 

What’s the equation you are trying to solve to get x?

11/36 is .305 repeating