One integer is 8 times another. if the product of the two integers is 128, then find the integers

Let's assign some variable:
x = smaller integer
y = bigger integer

We can set this up as an expression:



Solve for a variable in the first equation, y is already given, so plug that into the second equation:





Since we only care about the positive values (scalar multiplication), we can rule out the -4, and we are left with x = 4. y is 8 times x, so it has to be 32. Your final  x = 4, y = 32

Abc4n: 2mm: n2: 41: 2m: n=1: 2