You roll two six-sided fair number cubes. what is the probability that you will roll a sum greater than 6?

Total possible outcomes = 6 x 6  = 36

Listed here are all the possible 36 outcomes:
(1,1)(1,2)(1,3)(1,4)(1,5)(1,6)(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

Total outcomes that have a sum greater than 6 = 21

Listed here are the possible outcome greater than 6:
(1,6)(2,5)(2,6)(3,4)(3,5)(3,6)(4,3)(4,4)(4,5)(4,6)(5,2)(5,3)(5,4)(5,5)(5,6)(6,1)(6,2)(6,3)(6,4)(6,5)(6,6)

P(sum greater than 6)  = 21/36 = 7/12

P(sum greater than 6) = 7/12

Google it that might work