Mathematics, 25.07.2019 01:30 bpo2205748
Determine ƒ(–a) where ƒ(x) = x2– 6x and simplify. ƒ(–a) = a2 – 6a ƒ(–a) = –a2 + 6a ƒ(–a) = a2 + 6a ƒ(–a) = –a2 – 6a
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Determine ƒ(–a) where ƒ(x) = x2– 6x and simplify. ƒ(–a) = a2 – 6a ƒ(–a) = –a2 + 6a ƒ(–a) = a2 + 6a ƒ...
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