Your answer was: Â "g+11 over/ 2x+15 " .Â
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Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ;Â you should have put: Â "(x + 11)" .
As a matter of technicality, you could have/should have stated:
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 { Â
 } ; {Â
 }.Â
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   →   {but this would depend on the context — and/or the requirements of the course/instructor.}.  Good job!
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Explanation:
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Given: Â g(x) = Â
;
Find: Â g(x+5) .
Â
To do so, we plug in "(x+5)" for all values of "x" in the equation; & solve:
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    Start with the "numerator":  "(x + 6)" :
→  (x + 5 + 6) = x + 11 ;Â
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Then, examine the "denominator" : Â "(2x + 5)"
→ 2(x+5) + 5 ;Â
  →  2(x + 5) = 2*x + 2*5 = 2x + 10 ; Â
→ 2(x+5) + 5 =Â
    2x + 10 + 5 ;Â
  =  2x + 15 ;Â
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→  g(x + 5) = Â
 .Â
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Note that the "denominator" cannot equal "0" ;
     since one cannot "divide by "0" ;Â
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So, given the denominator: Â "2x + 15" ;Â
→  at what value for "x" does  the denominator, "2x + 15" , equal "0" ?
→  2x + 15 = 0 ;Â
Subtract "15" from each side of the equation:
→  2x + 15 - 15 = 0 - 15 ;Â
to get:Â
→  2x = -15 ;Â
Divide EACH SIDE of the equation by "2" ;Â
  To isolate "x" on one side of the equation; & to solve for "x" ;Â
→  2x / 2  =  -15 / 2 ;Â
to get:Â
→  x = - 7. 5 ; Â
Your answer was: Â "g+11 over/ 2x+15 " .Â
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ;Â you should have put: Â "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
 { Â
 } ; {Â
 }.Â
________________________________________________________
   →   {but this would depend on the context — and/or the requirements of the course/instructor.}.  Good job!
________________________________________________________
So; Â "Â
" .
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Now, examine the "denominator" from the original equation:
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→  "(2x + 5)"  ; Â
→  At what value for "x" does the 'denominator' equal "0" ?Â
→  2x + 5 = 0 ;Â
Subtract "5" from each side of the equation:Â
→  2x + 5 - 5 = 0 - 5 ;Â
to get:
→  2x = -5 ;Â
Divide each side of the equation by "2" ;Â
   to isolate "x" on one side of the equation; & to solve for "x" ;Â
→  2x / 2 = -5 / 2 ;
→  x = -2.5 ;Â
→  So;  "Â
" .
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The correct answer is:
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 →  g(x + 5) = Â
;
     { Â
} ; {Â
 }.Â
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→ Your answer was:  "g+11 over/ 2x+15 " .Â
____________________________________________________
Your answer was "incorrect —but almost correct" !
Instead of "(g + 11)" for the "numerator" ; you should have put: Â "(x + 11)" .
As a matter of technicality, you could have/should have stated:
________________________________________________________
 { Â
 } ; {Â
 }.Â
________________________________________________________
   →   {but this would depend on the context — and/or the requirements of the course/instructor.}.  Good job!
________________________________________________________