In circle a shown below, bd with a line above is the diameter and the measure of arc cb is 54 degrees. what is the measure of angle dbc

The complete question in the attached figure

we know that
the triangle ACB is an isosceles triangle
AC=AB----------> equals to the radius
so
∡ACB=∡CBA
the angle ∡CAB is equals to 54° by central angle
so
180°=54°+2*∡CBA--------> ∡CBA=[180-54]/2-----> 63°
∡CBA=63°
∡DBC=∡CBA-----------> ∡DBC=63°

the answer is
∡DBC=63°

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