Apotato is launched into the air at a velocity of 60 feet per second off of a building that is 210 feet tall. this can be modeled by the formula h=-16t^(2)+60t+210, where h is the height (in feet) after t seconds. when will the potato hit the ground? (round to the nearest second.)

The equation models the height of a projectile in feet above ground (h=0) with g=-32 ft/s^2 at a height of 210 ft. with an initial velocity (upwards) of 60 ft/s.

The time it takes to reach the ground can be obtained by solving the equation h(t)=0.

h(t)=0 =>
-16t^2+60t+210=0
=>
16t^2-60t-210=0
Solve by completing the square:
t^2-(60/16)t-210/16=0
=>
(t-60/32)^2=(60/32)^2-210/16
Simplify
t-15/8= ± sqrt(1065)/8
=>
t=15/8 ± sqrt(1065)/8
=-2.20 s. or 5.95 seconds  (to two decimals).

after 5.95 seconds, the potato will hit the ground, assuming no air resistance.

Hello!

the answer is:

the lateral area is equal to

why?

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!