Suppose you are flying a kite that is 50 feet long. while flying, there is a constant gust of wind that blows the kite to an angle of 60° with the ground. how high, in feet, is the kite above the ground

Height of the kite above the ground =  43.301270189  feet

Step-by-step explanation:

The illustration above forms a right angled triangle. The right angle triangle have an hypotenuse, adjacent side and opposite sides.

The hypotenuse is given as 50 feet , the angle with the ground is 60°. Using the SOHCAHTOA principle we can find the height of the kite above the ground which is the opposite side .

sine 60°  = opposite/hypotenuse

sine 60° = opposite/50

0.8660254038 = opposite/50

cross multiply

opposite = 0.8660254038 × 50

opposite =  43.301270189  feet

Height of the kite above the ground =  43.301270189  feet

The image below is what the illustration forms(right angled triangle)

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

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