Acircle has a diameter of 12 units, and its center lies on the x-axis. what could be the equation of the circle? check all that apply. (x – 12)2 + y2 = 12 (x – 6)² + y² = 36 x² + y² = 12 x² + y² = 144 (x + 6)² + y² = 36 (x + 12)² + y² = 144

Options 2 and 5.

Step-by-step explanation:

The standard form of a circle is

     ... (1)

where, (h,k) is center and r is radius.

We need to find the circle that has a diameter of 12 units, and its center lies on the x-axis.

So, radius of required circle must be 6 and center is in the form of (a,0).

The first equation is

      .... (2)

On comparing (1) and (2) we get  

Center of the circle is (12,0) and radius is . So, option 1 is incorrect.

Similarly,

For equation 2, center of the circle is (6,0) and radius is . So, option 2 is correct.

For equation 3, center of the circle is (0,0) and radius is . So, option 3 is incorrect.

For equation 4, center of the circle is (0,0) and radius is . So, option 4 is incorrect.

For equation 5, center of the circle is (-6,0) and radius is . So, option 5 is correct.

For equation 6, center of the circle is (-12,0) and radius is . So, option 6 is incorrect.

Therefore, the correct options are 2 and 5.

3=log(n)=2

answer a: product property

answer: 1, 3 and 5 are correct

step-by-step explanation: